Python: Find the highest value in a group
In my continued playing around with a How I met your mother data set I needed to find out the last episode that happened in a season so that I could use it in a chart I wanted to plot.
I had this CSV file containing each of the episodes:
$ head -n 10 data/import/episodes.csv NumberOverall,NumberInSeason,Episode,Season,DateAired,Timestamp 1,1,/wiki/Pilot,1,'September 19, 2005',1127084400 2,2,/wiki/Purple_Giraffe,1,'September 26, 2005',1127689200 3,3,/wiki/Sweet_Taste_of_Liberty,1,'October 3, 2005',1128294000 4,4,/wiki/Return_of_the_Shirt,1,'October 10, 2005',1128898800 5,5,/wiki/Okay_Awesome,1,'October 17, 2005',1129503600 6,6,/wiki/Slutty_Pumpkin,1,'October 24, 2005',1130108400 7,7,/wiki/Matchmaker,1,'November 7, 2005',1131321600 8,8,/wiki/The_Duel,1,'November 14, 2005',1131926400 9,9,/wiki/Belly_Full_of_Turkey,1,'November 21, 2005',1132531200
I started out by parsing the CSV file into a dictionary of (seasons -> episode ids):
import csv from collections import defaultdict seasons = defaultdict(list) with open('data/import/episodes.csv', 'r') as episodesfile: reader = csv.reader(episodesfile, delimiter = ',') reader.next() for row in reader: seasons[int(row[3])].append(int(row[0])) print seasons
which outputs the following:
$ python blog.py defaultdict(<type 'list'>, { 1: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22], 2: [23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44], 3: [45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64], 4: [65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88], 5: [89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112], 6: [113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136], 7: [137, 138, 139, 140, 141, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159, 160], 8: [161, 162, 163, 164, 165, 166, 167, 168, 169, 170, 171, 172, 173, 174, 175, 176, 177, 178, 179, 180, 181, 182, 183, 184], 9: [185, 186, 187, 188, 189, 190, 191, 192, 193, 194, 195, 196, 197, 198, 199, 200, 201, 202, 203, 204, 205, 206, 207, 208]})
It’s reasonably easy to transform that into a dictionary of (season -> max episode id) with the following couple of lines:
for season, episode_ids in seasons.iteritems(): seasons[season] = max(episode_ids) >>> print seasons defaultdict(<type 'list'>, {1: 22, 2: 44, 3: 64, 4: 88, 5: 112, 6: 136, 7: 160, 8: 184, 9: 208})
This works fine but it felt very much like a dplyr problem to me so I wanted to see whether I could write something cleaner using pandas.
I started out by capturing the seasons and episode ids in separate lists and then building up a DataFrame:
import pandas as pd from pandas import DataFrame seasons, episode_ids = [], [] with open('data/import/episodes.csv', 'r') as episodesfile: reader = csv.reader(episodesfile, delimiter = ',') reader.next() for row in reader: seasons.append(int(row[3])) episode_ids.append(int(row[0])) df = DataFrame.from_items([('Season', seasons), ('EpisodeId', episode_ids)]) >>> print df.groupby('Season').max()['EpisodeId'] Season 1 22 2 44 3 64 4 88 5 112 6 136 7 160 8 184 9 208
Or we can simplify that and read the CSV file directly into a DataFrame:
df = pd.read_csv('data/import/episodes.csv', index_col=False, header=0) >>> print df.groupby('Season').max()['NumberOverall'] Season 1 22 2 44 3 64 4 88 5 112 6 136 7 160 8 184 9 208
Pretty neat. I need to get more into pandas.
Reference: | Python: Find the highest value in a group from our WCG partner Mark Needham at the Mark Needham Blog blog. |